n=3^3-5=4^2+n

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Solution for n=3^3-5=4^2+n equation: 



n=3^3-5=4^2+n

We move all terms to the left:

n-(3^3-5)=0

We add all the numbers together, and all the variables

n-22=0

We move all terms containing n to the left, all other terms to the right

n=22

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